Question

x drives 6km towards north then 8 km towords east.how far and inwhich direction is the from his starting point?

Answer 1

use pythagorous thm,

$h ^{2} = \sqrt{{b ^{2} } + {p}^{2} }$
${h}^{2} = \sqrt{{6 ^{2} } + {8}^{2} }$
${h}^{2} = \sqrt{100}$
$h = 10$
is the distance from his starting point and he is in North-East direction

Answer 2

x is 10 km from his starting point in the North East direction

We can conclude from the question that x has moved along 2 sides of a right angled triangle.

Using pythagorean theorem, we can find the distance using the formula:

a^2 + b^2 = c^2, where c is the hypotenuse

a=8

b=6

c=root( a^2 + b^2)

=root(100)

=10 km in the North East direction