Question

x=e^m+e^-m/2 , y=e^m-e^-m/2 find dy/dx ?

Answer 1

Answer:

$\frac{x}{y}$ is the answer

Step-by-step explanation:

x=$\frac{e^{m}+e^{-m} }{2}$

$\frac{dx}{dm}$ = $\frac{e^{m}-e^{-m} }{2}$ = y------------ (i)

y = $\frac{e^{m}+e^{-m} }{2}$

$\frac{dy}{dm}$ = $\frac{e^{m}+e^{-m} }{2}$ = x -----------(ii)

$\frac{(ii)}{(i)}$ do it

$\frac{dy}{dx}$=$\frac{x}{y}$

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