Question

X equals to 3 + 2 root 2 then value of x square - 6 X + 1​

Answer 1

♡Question♡:-

$x =( 3 + 2 \sqrt{2} ) \: then \: find \: the \: value \: of \: (6x + 1)$

♡Answer♡:-

Given,

$x = (3 + 2 \sqrt{2} )$

So,

$6x + 1 \\ = 6(3 + 2 \sqrt{2} ) + 1 \\ = 18 + 12 \sqrt{2} + 1 \\ = 18 + 1 + 12 \sqrt{2} \\ = 19 + 12 \sqrt{2} (ans)$

It may help you.

♡Thank you♡

Answer 2

Answer:

18√2+1

Step-by-step explanation:

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