X finishes 7)10 of the work in 15 days he finished remaining work with help of e in 4 days .In how many x as qell as e could finish entire work together
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7/10 part of work has been completed by A in 15 days. Then,
Rest work = 1-(7/10) = 3/10 part.
Given, That 3/10 part of the work is completed by A and B together in 4 days. Means,
(A+B) completed the 3/10 of work in 4 days.
So, (A+B)'s 1 day's work = 3/(10*4) = 3/40;
Hence,
(A+B) can complete the work in 40/3 = 13(1/3) days.
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