Question

X finishes a work 3 days earlier than Y.Y do it for 4 days then leaves the rest of the work was finished by X alone thus the work was completed in 14 days How much time X and Y each will take separately to finish it : ​

wrong answer will report

Answer 1

Total days taken = 14 days

x finishes his work in = 3 days

y do work for 4 days and leave it for x which is equal to = 14-3-4

= 7

so total work of x = 7 + 3

= 10

y's working days = 4

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