( {(x + \frac{1}{a} )})^{2} - {b}^{2} = 0
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(x+1/a)²-b²=0
x2+2x/a+1/a²-b²=0
D=0
D=b²-4ac
D=4/a²-4(1/a²-b²)
D=4b²
x= -b+ √D/2a ,x= -b-√D/2a
x= -b -1/a
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