Question

X g of mgso4 (i = 1.8) is in 2.5 l of solution has an osmotic pressure of 2.463 atm. at 27oc. what is the value of x in g?

Answer 1

Answer:

hey nice question keep it up..

here is ur ans

π=iMRT

M=MOLARITY

HERE

π=2.46 atm

t=273+27=300k

i=1.8

volume of solution =2.5 l

so put it 2.46=1.8 mass of solute/120*1/2.5

mass of solute=2.46×120×2.5/1.8

solve=410g

hope so helpful...