Question

x g of potassium chlorate on decomposing produced 1.92 g of oxygen and 2.96 g of potassium chloride. what is the value of x​

Answer 1

Given :

• x g of Potassium chlorate on decomposing produced 1.92 g of oxygen and 2.96 g of potassium chloride.

To find :

• The value of 'x'

Concept used :

The total mass of the reactants should be equal to the total mass of the products (independent of physical state of the substances) . This is known as Law of conservation of mass.

Explanation :

The decomposition of potassium chlorate KClO₄ can be represented as,

$\cdot \: {\boxed{ \red{ \rm{KClO_4 \longrightarrow \: O_2 + KCl}}}}$

Now , According to the question ,

$\rm \:KClO_4 \longrightarrow \: O_2 + \: \: \: KCl \\ \rm (x \: g) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1.92 \: g) \: \: \: (2.96 \: g)$

Applying the Law of Conservation of mass ,

$: \implies \rm \: x \: = 1.92 \: g + 2.96 \: g \\ \\ : \implies \rm \: x \: = 4.88 \: g$

Hence , The Value of 'x' is 4.88 g

Answer 2

Answer:

Given :

x g of Potassium chlorate on decomposing produced 1.92 g of oxygen and 2.96 g of potassium chloride.

To find :

The value of 'x'

Concept used :

The total mass of the reactants should be equal to the total mass of the products (independent of physical state of the substances) . This is known as Law of conservation of mass.

Explanation :

The decomposition of potassium chlorate KClO₄ can be represented as,

\cdot \: {\boxed{ \red{ \rm{KClO_4 \longrightarrow \: O_2 + KCl}}}}⋅

KClO

4

⟶O

2

+KCl

Now , According to the question ,

\begin{gathered} \rm \:KClO_4 \longrightarrow \: O_2 + \: \: \: KCl \\ \rm (x \: g) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1.92 \: g) \: \: \: (2.96 \: g)\end{gathered}

KClO

4

⟶O

2

+KCl

(xg)(1.92g)(2.96g)

Applying the Law of Conservation of mass ,

\begin{gathered} : \implies \rm \: x \: = 1.92 \: g + 2.96 \: g \\ \\ : \implies \rm \: x \: = 4.88 \: g\end{gathered}

:⟹x=1.92g+2.96g

:⟹x=4.88g

Hence , The Value of 'x' is 4.88 g