Question

X geys 25% more than y and y gets 20% more than z...The share of z out of a sum of rs 740 is what salary in 1999

Answer 1

Solution:

Let share of z = k

As given , y gets 20% more than z.

So, share of y = k + $\frac{20 k}{100}$

      = $\frac{120 k}{100}$

Also, it is given that x gets 25% more than y .

Share of x= $\frac{120 k}{100} + \frac{25}{100} \times \frac{120 k}{100}=\frac{120 k}{100} \times \frac{125}{100}=\frac{3 k}{2}$

If Salary = Rs 740

To find the value of k,we will have to use

$\frac{3 k}{2}= 740 \\\\ k=\frac{740 \times 2}{3}=\frac{1480}{3}$

Share of z in salary of Rs 740 is Rs $\frac{1480}{3}$

If Salary = Rs 1999

$\frac{3 k}{2}= 1999 \\\\ k=\frac{1999 \times 2}{3}=\frac{3998}{3}$

Share of z in salary of Rs 1999 is Rs $\frac{3998}{3}$

So, The share of z out of a sum of rs 740 is of salary in Rs 1999=  $\frac{\frac{1480}{3}}{\frac{3998}{3}}\times 100=37.018$ %

Answer 2

Z share = Z,

Y = 1.2Z

X = 1.25×1.2Z,

X+Y+Z =740

(1.25× 1.2+1.2+1)Z=740

3.7Z=740, Z=200