Question

X gram of a metal(equivalent weight=12) was completely dissolved in 100 cc of N/2 HCl solution. The volume was then made upto 500cc. It is found that 25 cc of dilluted acid solution required 17.5cc of N/10 NaOH for complete neutralization. Find the value of x.

Answer 1

Answer:

For HCl 

Molarity = Normality

Gram equivalents of HCl = Normality × Volume in litres

=2N×100×10−3L

=0.2 eq

For complete neutralisation

Gram equivalents of HCl = Gram equivalents of metal carbonate

Equivalent weight of metal carbonate =Weight of metal carbonateGram equivalents of metal carbonate

=10g0.2eq=50 g/eq

Equivalent weight of carbonate (CO2−3)=12+(3×16)2=30 g/eq

Equivalent weight of metal carbonate = Equivalent weight of metal + Equivalent weight of carbonate

50 g/eq = x + 30 g/eq

x = 20 g/eq

∴ Equivalent weight of metal is 20 g/eq

Answer 2

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