(x>0)
f(x)=(x^t +1 ) / (x^t -1)
The limit of the function as t tends to infinity,
(A) does not exist; (B) exists and is everywhere continuous;
(C) exists and is discontinuous at exactly one point,
(D) exists and is discontinuous at exactly two points.
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Step-by-step explanation:
Therefore this function will be discontinuous when X is 1 and for all other values it will be continuous.
so I guess the answer is
(C) exists and is discontinuous at exactly one point.
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