} ৭ + ৭ + ৭ = ১ X ৭ ২৪৭ -এর আগের এবং পরের সংখ্যা দুটি লিখে > বা < চিহ্ন দাও।t
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Solution -
We Have ,
\begin{gathered} \large \sf{a_{5} +a_{7} = 52}\\ \\ \large \sf{ = a + 4d + a + 6d= 52}\\ \\ \large \sf2a + 10d \: \: - - - (1)\\ \\ \large \sf{a_{11} = a + 10d = 46} \\ \\ \end{gathered}
a
5
+a
7
=52
=a+4d+a+6d=52
2a+10d−−−(1)
a
11
=a+10d=46
♠ Multiplying Both Sides by 2 :
\begin{gathered}\large :\longmapsto\sf 2a + 20d = 92\: \: - - - (2) \\ \end{gathered}
:⟼2a+20d=92−−−(2)
♠ Subtracting (1) From (2) , We get :-
\begin{gathered}\sf10d = 40 \\ \\ \sf d = \cancel{\frac{40}{10} }\\ \\ \purple{ \Large :\longmapsto \underline {\boxed{{\bf d = 4} }}}\end{gathered}
10d=40
d=
10
40
:⟼
d=4
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