x =h+acos , y = k +b sin e
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Given,
x=h+acosθ
y=k+asinθ
Now,
x−h=acosθ
y−k=asinθ
On squaring and adding we get,
(x−h)
2
+(y−k)
2
=a
2
cos
2
θ+a
2
sin
2
θ
=a
2
(sin
2
θ+cos
2
θ)
=a
2
(1) Since [sin
2
θ+cos
2
θ=1].
Hence proved.
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