Math, asked by shubhranshuchintu, 1 year ago

X has twice as much money as that of y and y has 50% more money than that of z. If the average money of all of them is 110, then the money, which x has,​

Answers

Answered by sahibnarula
0

Answer:

7.9approx

Step-by-step explanation:

x=2y

y=y

z=50%y+y

average money=x+y+z/3

=2y+y+50y+y

____________=110

3×100

=90y/300=110

=y=110×300/90

=x=2×110×300/90

=7.9(approx)

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