Question

(x+i)^2
If a +ib = ,then prove that a^2 + b^2
(2x2 +1)
(x2 +1)
(2x2 +1)2​

Answer 1

Answer:

(x^2 + 1)^2

Step-by-step explanation:

the question is not clear.

still..I proceed with what I got..

(x+I)^2 = a+ ib

x^2 + i^2 +2xi = a + ib

x^2 - 1 + 2xi = a + ib

this gives..

a = x^2 - 1

b = 2x

Now,

a^2 + b^2

= (x^2 - 1)^2 +(2x)^2

x^4 - 2x^2 + 1 + 4x^2

= x^4 + 2x^2 + 1

= (x^2 + 1)^2