Question

X
In a coitain race there are three boys A, B, C.
The winning provability of his twice than B
& the winning probability of B is turiu than c.
What are their probabilities of winning.​

Answer 1

Answer:

P(A) = 60%

P(B) = 30%

P(C) = 10%

Step-by-step explanation:

P(A) = 6p ; P(B) = 3p ; P(C) = p

P(A) + P(B) + P(C) = 1

6p + 3p + p = 1

10p = 1

p = 1/10

Thus,

P(A) = 6/10 or 3/5 or 60%

P(B) = 3/10 or 30%

P(C) = 1/10 or 10%