Question

(x) In quadrilateral ABCD, BMLAC and DN 1 AC AC = 22cm, BM = 3cm and
DN = 3cm. Find the area of quadrilateral ABCD.​

Answer 1

Answer:

area of quadrilateral= 1/2 ×diagonal (h1×h2)

Answer 2

Answer:

66cm^2 is the answer

Step-by-step explanation:

To find the area of quadrilateral ABCD, first we have to find the area of ΔABC, and ΔADC Area of ΔABC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Area of ΔADC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Then,

Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC

= 33 + 33

= 66 cm2