Question

X-intercept of the line 2x+3y-4=0 is
Please answer as soon as possible :)

Answer 1

We solve the given line 2x+3y=4 for y as follows:

2x+3y=4

⇒3y=−2x+4

⇒y=

3

−2x+4

⇒y=−

3

2x

+

3

4

(1)

We know that the equation of a line is y=mx+c where m is the slope of the line and c is the y-intercept.

Comparing the equation of line y=mx+c with equation 1 we have,

m=−

3

2

and c=

3

4

Hence, the slope of the line is −

3

2

and the y-intercept is

3

4

.

Answer 2

Answer:

First, convert this equation into slope-intercept form.

2x + 3y + 4 = 0

Subtract 4 and 2x from both sides:

3y = -2x-4

Divide both sides by 3:

y = -2/3x - 4/3

Set x equal to zero to find the y-intercept:

y = -2/3*0 - 4/3

y = -4/3

Thus, the y-intercept is at (0, -4/3)

Now, set y equal to zero to find the x-intercept. You do this by solving for x when y = 0.

y = -2/3x - 4/3

y = 0

0 = -2/3x - 4/3

Add 4/3 to both sides:

4/3 = -2/3x

Multiply both sides by 3 to get rid of the fractions:

4 = -2x

Divide both sides by -2:

x = -2

Thus, the x-intercept is at (-2,0).

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