X is a 5 digit number when we subtract the sum of the digits form x, it becomes divisible by
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Answer:
let us assume X the 5 digits number divisible by 9
so it is = 9k
As the sum of digits of the X would also be divisible by 9
so it's 9k'
now subtract 9k - 9k' = 9(k-k')
As k - k' is an integer
so it is divisible by 9
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