X is a 5 digit number when we subtract the sum of the digits form X, it becomes divisible by _____ A .5 B .1 C.9 D.6
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let 5 digit no divisible by 9
so it's 9k
As sum of digits would also be divisible by 9
so it's 9 k'
now subtract 9k - 9k ' = 9(k-k')
As k - k' is integer
so it's divisible by 9
so it's 9k
As sum of digits would also be divisible by 9
so it's 9 k'
now subtract 9k - 9k ' = 9(k-k')
As k - k' is integer
so it's divisible by 9
hemaattoti:
why you have taken it as 9?Why not other digits?
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