Math, asked by 8903m4ja, 7 months ago

X is a 6-digit number that satisfies all these conditions:

When X is rounded off to the nearest hundred thousand, the result is three hundred thousand.
When X is rounded off to the nearest ten thousand, the sum of the digits of the resulting number is 7.
When X is rounded off to the nearest thousand, the sum of the digits of the resulting number is 9.
The face value of the digits in the hundreds, tens, and ones place is the same.
The digit in the hundreds, tens, and one's place is an odd number.
Find one such value of X

Answers

Answered by shirshaPradhan
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anuanandsmsanuanandsms13.08.2020MathPrimary School+5 ptsAnswered

anuanandsmsanuanandsms13.08.2020MathPrimary School+5 ptsAnsweredA is a 8-digit number that satisfies all these conditions: When A is rounded off to the nearest million, the result is 55 million. When A is rounded off to the nearest hundred thousand, the result is 55,200,000. When A is rounded off to the nearest ten thousand, the sum of the digits at the hundred thousand and ten thousand place is 6. When A is rounded off to the nearest thousand, the sum of the digits at the hundred thousand, ten thousand, and thousand place is 9. The hundreds, tens, and ones place have the same odd number. The sum of the digits at hundreds, tens, and ones place is 21.

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