Math, asked by ReenaRobin, 1 year ago

X is a point on the side BC of∆ABC . XM and XN are drawn parallel to AB and AC respectively meeting AB in N and AC in M . MN produced meets CB produced at T . prove that TX^2= TB×TC.
please send me the answer fast

Answers

Answered by abhi4183
1

Its answer is also same as last two questions.

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