X is a point on the side BC of∆ABC . XM and XN are drawn parallel to AB and AC respectively meeting AB in N and AC in M . MN produced meets CB produced at T . prove that TX^2= TB×TC.<br />please send me the answer fast
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In triangle TXM
BN parallel XM so by Bpt
TN/NM=TB/TX_______i
In triangle TCM
XM parallel CM so by Bpt
TN/NM=TX/XC______ii
from ____i and ____ii
TB/TX=TX/XC
TX^2= TB×XC.
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