Question

X is an inorganic compound having molecular weight is 218 then what is the chemical formula of X is​

Answer 1

Answer:

Let the compound be C

x

H

y

N

z

.

Mass of C=12x

Mass of H=y

Mass of N=14z

Total Mass =12x+y+14z

Mass % of C=

(12x+y+14z)

12x

×100

Now given,

(I) Mass % of C=6× mass % of H

⟹12x=6y

⟹y=2x

(II) Mass % of C+ Mass % of H=1.5 (mass % of N)

⟹12x+y=1.5×14z

⟹12x+2x=21z

⟹x=1.5z

and y=3z.

So, the compound can be expressed as C

1.5z

H

3z

N

z

or C

3z

H

6z

N

2z

.

Now choosing, z=1, we have C

3

H

6

N

2

.

Molecular weight = 3×12+6×1+2×14=70 g/mol

Given molecular weight >100.

So, when we choose z=2, we have C

6

H

12

N

4

.

Molecular weight = 6×12+12×1+4×14=140 g/mol which is greater than 100.

Explanation:

good evening hope it will help you follow me And brainlist me