Question

x is an integer such that it leaves a remainder of 2 when divided by 3, leaves a remainder of 3 when divided by
5, and leaves a remainder of 5 when divided by 7. What could be a possible value of x ?

Answer 1

Heya........!!!!

According to the questions, the number is
=> x = 3Q1 + 2

it is also given that -- x = 5Q2 + 3 and
x = 7Q3 + 5 .

all these equations are equal to ' x ' so let us equate these equations .

=> x = 3Q1 + 2 = 5Q2 + 3 = 7Q3 + 5 .

from solving the above we takes out the value of Q1 , Q2 .

=> we get Q1 = 22 , . Q2 = 13

➡So ,, putting the value of Q1 , Q2 we get x = 68.



Hope It Helps You ^_^