Question

X is equals to 7 + 4 root 3 then find the value of x minus one upon x.
Guy's please answer me this question immediately. ​

Answer 1

$x = 7 + 4 \sqrt{3} \\ x - \frac{1}{x} \\ = 7 + 4 \sqrt{3} - \frac{1}{7 + 4 \sqrt{3} } \\ = \frac{{(7 + 4 \sqrt{3}) }^{2} - 1}{7 + 4 \sqrt{3} } \\ = \frac{49 + 48 + 56 \sqrt{3} - 1 }{7 + 4 \sqrt{3} } \\ = \frac{96 + 56 \sqrt{3} }{7 + 4 \sqrt{3} } \\ = \frac{96 + 56 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } \\ = \frac{(96 + 56 \sqrt{3})(7 - 4 \sqrt{3} ) }{49 - 48} \\ = (96 + 56 \sqrt{3} )( 7- 4 \sqrt{3} )$

HOPE THIS ANSWER HELPS PLZ MARK AS BRAINLIEST.