Math, asked by gautamcholkar9196, 10 months ago

X is three times more efficient worker than y is, therefore, able to complete a work in 60 days earlier. How many days will they take together to complete the work?

Answers

Answered by spiderman2019
0

Answer:

22.5 days

Step-by-step explanation:

Let the number of days taken by A = x days,

Then number of days taken by B = 3x days (as A is thrice as efficient as B).

According to the question,

3x - x = 60 days, hence x = 30 days

The number of days taken by A = 30 days,

Number of days taken by B = 90 days

Total units of work = LCM (30 , 90) units = 90 units

Work done by A in one day = 90/30 = 3 units per day  

Work done by B in one day = 90/90 = 1 unit per day.

Total units done by both A and B together in one day = 3 + 1 = 4 units per day

Hence, total number of days taken by both of them = Total work / Number of units done in one day = 90 / 4 = 22.5 days.

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