Question

x is three times old as y ,z was twice as old as x four year ago . in four year time ,x will be of 31 year .what is the present age of y and z
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Answer 1

Step-by-step explanation:

4 yrs ago , x=3y and z=2x=6y.

After 4 years,

x=3y+4, y= y+4,z=6y+4.

given, x=31yrs

so, 3y+4=31,

or, 3y=27

or, y=9yrs

present ages,

x=3×9+4=31,

y=13,

z=58.