X is twice as good a workman as Y and together they finish a piece of work in 18 days. In how many days will X alone finish the work?
Answers
Answered by
3
Given,
X=2y
X+Y=18
2Y+Y=18
3Y=18
Y=6
=>X=2×6
=>X=12
therefore x will finish the work in 12 days Hope it helps u
X=2y
X+Y=18
2Y+Y=18
3Y=18
Y=6
=>X=2×6
=>X=12
therefore x will finish the work in 12 days Hope it helps u
Answered by
1
a=2:1
a+b in a day=1/18
b in a day=1/8 * 1/3
=1/54
so b=54days
a+b in a day=1/18
b in a day=1/8 * 1/3
=1/54
so b=54days
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