Question

x+iy/2+3i+2+i/2+3i=9/13(1+i)​

Answer 1

x+iy/2+3i+2+i/2-3i=9/13(1+i)

(x+yi)(2-3i)+(2+i)(2+3i)(2+3i)(2-3i)=9/13(1+i)

2x-3xi+2yi-3yi2+4+6i+2i+3i2/4-9i=9+91/13

2x-3xi+2yi+3y+4+8i-3/13=9+9i/13

(2x+3y+1)+(8-3x+2y)l=9+9i

2x+3y+1=9 and 8-3x+2y=9

3x-2y=-1

22

3.0

ANSWERquestion 1 multiply by 2 and in equation 2

x 3

13x=13 ,x=2

putting x=1 in equation 1 we get

2(1)+3y=8

3y=6

y=2

answer is, x=1 and y=2

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