Question

x+iy =(2-3i) upon (4+5i)​

Answer 1

$x + iy = \frac{2 - 3i}{4 + 5i} \\ x + iy = \frac{(2 - 3i)(4 - 5i)}{(4 + 5i)(4 - 5i) } \\ x + iy = \frac{8 - 10i - 12i + 15 {i}^{2} }{16 - 25 {i}^{2} } \\ x + iy = \frac{8 - 15 - 22i}{16 + 25} \: \: \: \: \: ... \: ( {i}^{2} = 1) \\ x + iy = \frac{ - 7 - 22i}{41} \\ x + iy = ( \frac{ - 7}{41} ) + i( \frac{ - 22}{41} )$

On comparing L.H.S. and R.H.S.

x = $\frac{- 7}{41}$ and y = $\frac{- 22}{41}$