Question

(x+iY)+(3-2)=1+41 ?
$(x + iy) + (3 - 2) = 1 + 4i$
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Answer 1

Answer:

x = 0, y = 4

Step-by-step explanation:

Firstly, we need to rewrite (x+iy)+(3-2) in standard complex form:

(x+iy)+(3-2) = (x+iy)+1 = (x+1) + iy

Secondly, we use the fact that complex numbers are equal only in theur real and imaginary parts are equal:

x+1=1

y=4

Therefore, we have x=0, y=4