Math, asked by rupsbiswas147, 4 days ago

(x+iy)(3 + 2i) = 1+i​

Answers

Answered by lovelychristy143
1

Step-by-step explanation:

( x + iy )( 3 + 2i ) = 1+i

3x + 2xi + 3yi + 2yi^2 = 1 + i

3x +(2x + 3y)i - 2y = 1 + i

(3x - 2y) + (2x + 3y)i = 1 + i

3x - 2y = 1 => 6x - 4y = 2 (multiply with 2)

2x + 3y = 1 => 6x + 9y = 3(multiply with 3)

subtract these two equations,

-13y = -1

y = 1/13

sub. y value in eqn 1

3x - 2(1/13) = 1

3x = 1+2/13

3x = 15/13

x = 15/39

Similar questions