(x+iy)(3 + 2i) = 1+i
Answers
Answered by
1
Step-by-step explanation:
( x + iy )( 3 + 2i ) = 1+i
3x + 2xi + 3yi + 2yi^2 = 1 + i
3x +(2x + 3y)i - 2y = 1 + i
(3x - 2y) + (2x + 3y)i = 1 + i
3x - 2y = 1 => 6x - 4y = 2 (multiply with 2)
2x + 3y = 1 => 6x + 9y = 3(multiply with 3)
subtract these two equations,
-13y = -1
y = 1/13
sub. y value in eqn 1
3x - 2(1/13) = 1
3x = 1+2/13
3x = 15/13
x = 15/39
Similar questions