Question

x+ (k+1)y =4 and (k+1)x+9y =5k +2 has infinitely many solutions​

Answer 1

Answer:

x+(k+1)y=4→

(k+1)x+(k+1)²y=4k+4

(k+1)x+9y=5k+2

y=(2-k)/{(k²+2k-8}.

=-(k-2)/(k-2)(k+4)

=-1/(k+4)

x=5k+2–9y

=5k+2+9/(k+4)

=(5k²+20k+2k+8+9)/(k+4)

=(5k²+22k+17)/(k+4)