x+(k+1) y=5 (k+1) x+9y=8k-1 find k for infinity many solution
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This system of equation is of the form
a1x+b1y=c1
a2x+b2y=c2
where a1=1,b1=k+1,c1=5
and a2=k+1,b2=9 and c2=8k−1
For infinitely many solutions, we must have
a2a1=b2b1=c2c1
The given system of equations will have infinite solutions, if
k+11=9k+1=8k−15
⇒k+11=9
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