x=-k/2 , 2x^2+(k-3)x-3k=0
with full explanation
Answers
Answer:
Step-by-step explanation:
x=-k/2,
equation is,
2x²+(k-3)x-3k=0
2(-k/2)²+(k-3)(-k/2)-3k=0
k²/2 + k²/6 -3k =0
( 3k²+k²)/6 - 3k =0
4k²/6 -3k =0
2k²/3 - 3k =0
( 2k²-9k)/3 =0
2k²-9k=0
(2k-9)k=0
2k-9=0
2k=9
k=9/2
(or) k=4.5
please accept friend request if u like solution .
Answer:
blah blah blah.............