Question

x^k y^4(2x^3 + 7x^2y^4) = 2x^4y^4 + 7x^3y^8 what does k =

Answer 1

Answer:

1

Step-by-step explanation:

x^ky^4(2x^3 +7x^2y^4)= 2x^4y^4 + 7x^3y^8

x^k = 2x^4y^4 + 7x^3y^8 / y^4(2x^3 + 7x^2y^4)

x^k = 2x^4y^4 + 7x^3y^8 / 2x^3y^4 +7x^2y^8

x^k = x(2x^3y^4 +7x^2y^8) / 2x^3y^4 +7x^2y^8

x^k = x

x^k =x^1

k = 1