Question

X=Ka^mt^n gives the position of the body where 'a' is acceleration and 't'. Then evaluate dimension of m and n.​

Answer 1

Answer:

Position x=Kamtn

Writing the dimension on the both sides.

[M0LT0]=[LT−2]m[T]n

[M0LmT−2m+n]

On comparing both sides.

m=1

−2m+n=0

n=2m=2×1=2.

Explanation:

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