Question

x ki power x ki power x ki power 2017=2017 find the value of x.

Answer 1

x ki power x ki power x and so on would behave to draw a conclusion):

for x<1,x<1, yy becomes 0

for x=1,x=1, yy becomes 1

for x>1,x>1, yy becomes infinite

These 3 points is where the first problem lies. Are these true? If so, how do we reach to the conclusion?

Secondly, considering this to be true, I get the derivative at:

x<1x<1 to be 0.

x=1x=1 to be 1.

for x>1x>1, I took x=2.x=2. then the derivative dydx=y2/[2(1−ln(y))]dydx=y2/[2(1−ln(y))] (replacing xx by 22). Now, I ki power 2017=2017 find the value of x.applied L hospital's rule to get the value of the expression to be negative infinity.

This is the second problem. I have used L Hospital's rule, but limits were not concerned. Is this method valid? If not, how would we calculate it?

calculus derivatives infinity

Answer 2

your answer is 2017 ^1/2017

x=2017^1/2017