x ki power y = e ki power y-x then defferenceat
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x^y=e^(y-x)
Take logarithmic on both side
Logx^y=loge^(y-x)
Ylogx=y-x
Now differentiate
Y/x +logx dy/dx= dy/dx-1
Now solve it yourself algebraically
Take logarithmic on both side
Logx^y=loge^(y-x)
Ylogx=y-x
Now differentiate
Y/x +logx dy/dx= dy/dx-1
Now solve it yourself algebraically
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