X-ky=12; 3x+2y=-5 find k if there exists a unique solution
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x - ky = 2 ; 3x + 2y = -5
a1 = 1, b1 = -k ; a2 = 3, b2 = 2
For a unique solution,
a1/a2 ≠ b1/b2
1/3 ≠ -k/2
2/3 ≠ -k
k ≠ -2/3
Therefore, for any value of k except -2/3, the given system has a unique solution.
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