Question

X lies from 121 < x >1331, x^2 1 when divided by 11 what will not be the remainder

Answer 1

Answer:

Step-by-step explanation:

since x should be greater than 121, let us suppose that 'y' is no. which is greater than 0,

now we can write, x^2+1 as (121+y)^2 +1.

(y^2 + 121^2 + 2*121*y + 1)/11

y^2/11 + 121^2/11 + 2*121*y/11 + 1/11

y^2/11 + 0 + 0 + 1 ( remainder)

y^2/11 + 1

y^2 can be 1,4,9,16,25......

after dividing by 11,remainder we got 1,4,6 but not 8.

Hope it helps you....