Question

x lies from 121 < x >1331 x^2+1 when divided by 11 what will not be the remainder

Answer 1

The options for this question are missing. Here are the options:

A.1

B.4

C.6

D.8

Solution:

Since x should be greater than 121

Let us suppose that 'y' is no. which is greater than 0,

For this we can write, x^2+1 as (121+y)^2 +1.

(y^2 + 121^2 + 2*121*y + 1)/11

y^2/11 + 121^2/11 + 2*121*y/11 + 1/11

y^2/11 + 0 + 0 + 1 ( remainder)

y^2/11 + 1

y^2 can be 1,4,9,16,25..

Now we will divide this by 11 and the remainder we get it ,4,6 but not 8.

So the correct answer to this question is option D: 8