'X' litres of carbon monoxide is present
at STP. It is completely oxidised to CO2.
The volume of CO2 formed is 11.207
litres at STP. What is the value of X'in
litres?
A) 22.414
B) 11.207
C) 5.6035
D) 44.828
Answers
Answered by
18
Explanation:
2CO + 02 ------------> 2CO2
Volume of CO2 = 11.207
mole of CO2 = 11.207 / 22.7
No. of mole of CO = 11.207/22.7
Volume of CO = 11.207/22.7 × 22.7
= 11.207 L
Answered by
1
Answer:
11.207
Explanation:
according to Stoichiometric reaction
CO + 1/2O2>>>>>> CO2
At S.T.P
22.4 CO will give 22.4 CO2
And,
11.207 CO will give 11.207 CO2
Since the CO2 is given i.e. 11.207 is formed so from balanced equation it can be calculated that 11.207 CO was oxidized
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