x^log (2+x)^2 =25 Value is
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Precalculus
Solve for x log base x of 25=2
logx(25)=2logx(25)=2
Rewrite logx(25)=2logx(25)=2 in exponential form using the definition of a logarithm. If xx and bbare positive real numbers and bb≠≠11, then logb(x)=ylogb(x)=y is equivalent to by=xby=x.
x2=25x2=25
Take the square root of both sides of theequation to eliminate the exponent on the left side.
x=±√25x=±25
The complete solution is the result of both the positive and negative portions of thesolution.
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Simplify the right side of the equation.
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x=±5x=±5
The complete solution is the result of both the positive and negative portions of the solution.
Tap for more steps...
x=5,−5x=5,-5
Verify each of the solutions by substituting them back into the original equation logx(25)=2logx(25)=2 and solving. In this case, thesolution −5-5 was proven to be invalid during this process.
x=5x=5
pls mark me as brainliest
Popular Problems
Precalculus
Solve for x log base x of 25=2
logx(25)=2logx(25)=2
Rewrite logx(25)=2logx(25)=2 in exponential form using the definition of a logarithm. If xx and bbare positive real numbers and bb≠≠11, then logb(x)=ylogb(x)=y is equivalent to by=xby=x.
x2=25x2=25
Take the square root of both sides of theequation to eliminate the exponent on the left side.
x=±√25x=±25
The complete solution is the result of both the positive and negative portions of thesolution.
Tap for fewer steps...
Simplify the right side of the equation.
Tap for more steps...
x=±5x=±5
The complete solution is the result of both the positive and negative portions of the solution.
Tap for more steps...
x=5,−5x=5,-5
Verify each of the solutions by substituting them back into the original equation logx(25)=2logx(25)=2 and solving. In this case, thesolution −5-5 was proven to be invalid during this process.
x=5x=5
pls mark me as brainliest
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