Question

(x ^log A base 2 )+ (A ^ log X base 2) = 2a^2 [ a>1 ]​

Answer 1

Answer:

Step-by-step explanation:

Thanks for the A2A.

Let us assume 2log25=x

Now taking logarithm with base 2 on both sides we get,

log22log25=log2x [Since logaax=x]

or,log25=log2x

or,x=5

Actually you can this as a property in logarithm,

mlogmn=n

I hope the solution above gives you the idea of the proof of this property and helped you to understand it. If any doubt, feel free to ask in the comments.

Answer 2

Answer:

hope you will understand