x^log a to the base 2 + a^
log x to the base 2=2a^2.(a>1)
Answers
Answered by
0
Step-by-step explanation:
Thanks for the A2A. Let us assume 2log25=x. Now taking logarithm with base 2 on both sides we get,. log22log25= log2x [ ...
Answered by
0
Similar questions