Question

X + log of 1 + 2 raise to x to the base 10 is equals to X log of 5 to the base 10 + log of 6 to the base 10​

Answer 1

Answer:

x = 16.6

Step-by-step explanation:

Interpreting the question above;

x+log(1+2^x) = xlog5 + log 6

log10^x+log(1+2^x) = log5^x+log6

Removing log through sides

: . 10^x (1+2^x) = 5^x (6)

Let 5^x be p

(p) (1+2^x) = 6p

p+(p)2^x = 6p

5p = (p)2^x

: . 2^x = 5

Taking the log of both sides

xlog2 = 5

x = 5/log2 = 5/0.3010 = 16.611