Question

X
log, (x+3) base6- Log x base6
=2
Then x=--​

Answer 1

Answer:

Therefore x = 3/35

Step-by-step explanation:

I assume you're trying to ask:

$\\\tt log_{6}(x + 3) - log_{6}(x) = 2$

Using,

$\ \ \tt log_{a}(b) - log_{a}(c) = log_{a}( \dfrac{b}{c} )$

We have,

$\\\tt log_{6}( \dfrac{x + 3}{x} ) = 2$

Using basic log logic,

${6}^{2} = \dfrac{x + 3}{x} \\ 36x = x + 3 \\ 35x = 3 \\ \\ = \dfrac{3}{35}$

Answer 2

$\huge\bf\fbox\red{Answer:-}$

I assume you're trying to ask:

$\begin{gathered} \\\tt log_{6}(x + 3) - log_{6}(x) = 2 \end{gathered}$

Using,

$\ \ \tt log_{a}(b) - log_{a}(c) = log_{a}( \dfrac{b}{c} )$

We have,

$\begin{gathered}\\\tt log_{6}( \dfrac{x + 3}{x} ) = 2\end{gathered}$

Using basic log logic,

$\begin{gathered} {6}^{2} = \dfrac{x + 3}{x} \\ 36x = x + 3 \\ 35x = 3 \end{gathered}$

$x = \dfrac{3}{35}$