Question

X= (LOG X)^tany, then dy/dx is​

Answer 1

Answer:

रज्स्ब्स्ग्श्स्ब्स 638284

Answer 2

Step-by-step explanation:

$x = ({logx})^{tany} \\ \\ taking \: log \: on \: both \: sides \\ logx = tany \: log(logx) \\ \frac{1}{x} = \frac{tany}{x \: logx} + \frac{log(logx) \: {sec}^{2} y \: dy}{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: dx} \\ \frac{log(logx) \: {sec}^{2}y \: dy }{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: dx } = \frac{1}{x} - \frac{tany}{x \: logx} \\ \frac{log(logx) \: {sec}^{2} y \: dy}{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: dx} = \frac{logx - tany}{x \: logx} \\ \frac{dy}{dx} = \frac{logx - tany}{x \: logx \: \: . log(logx) {sec}^{2} y} \\ \\ \\ \\ hope \: this \: will \: help \: you....$